Decimal.Decrement(Decimal) Operator

Definitie

Naamruimte:
System
Assembly's:
mscorlib.dll, System.Runtime.dll
Assembly's:
netstandard.dll, System.Runtime.dll
Assembly:
System.Runtime.dll
Assembly:
mscorlib.dll
Assembly:
netstandard.dll
Bron:
Decimal.cs
Bron:
Decimal.cs
Bron:
Decimal.cs
Bron:
Decimal.cs
Bron:
Decimal.cs

Hiermee wordt de Decimal operand met één afgebouwd.

public:
 static System::Decimal operator --(System::Decimal d);
public:
 static System::Decimal operator --(System::Decimal d) = System::Numerics::IDecrementOperators<System::Decimal>::op_Decrement;
public static decimal operator --(decimal d);
static member op_Decrement : decimal -> decimal
Public Shared op_Decrement (d As Decimal) As Decimal

Parameters

d
Decimal

De waarde die moet worden afgebroken.

Retouren

Decimal

De waarde van d afgebroken door 1.

Implementeringen

Decrement(TSelf)

Uitzonderingen

OverflowException

De retourwaarde is kleiner dan Decimal.MinValue of groter dan Decimal.MaxValue.

Opmerkingen

De Decrement methode definieert de werking van de operator voor verlagen voor Decimal waarden. Hiermee schakelt u code in, zoals de volgende:

using System;

public class Example
{
   public static void Main()
   {
      Decimal number = 1079.8m;
      Console.WriteLine("Original value:    {0:N}", number);
      Console.WriteLine("Decremented value: {0:N}", --number);
   }
}
// The example displays the following output:
//       Original value:    1,079.80
//       Decremented value: 1,078.80

let number = 1079.8m
printfn $"Original value:    {number:N}"
printfn $"Decremented value: {- -number:N}"

// The example displays the following output:
//       Original value:    1,079.80
//       Decremented value: 1,078.80

Sommige talen (zoals Visual Basic) die geen incrementele operator hebben, kunnen de methode Decrement rechtstreeks aanroepen, zoals in het volgende voorbeeld wordt weergegeven.

Module Example
   Public Sub Main()
      Dim number As Decimal = 1079.8d
      Console.WriteLine("Original value:    {0:N}", number)
      Console.WriteLine("Decremented value: {0:N}", Decimal.op_Decrement(number))
   End Sub
End Module
' The example displays the following output:
'       Original value:    1,079.80
'       Decremented value: 1,078.80

Als uw taal geen aangepaste operators ondersteunt, roept u de Subtract methode aan, zoals in het volgende voorbeeld wordt weergegeven.

using System;

public class Example
{
   public static void Main()
   {
      Decimal number = 1079.8m;
      Console.WriteLine("Original value:    {0:N}", number);
      Console.WriteLine("Decremented value: {0:N}", Decimal.Subtract(number, 1));
   }
}
// The example displays the following output:
//       Original value:    1,079.80
//       Decremented value: 1,078.80

open System

let number = 1079.8m
printfn $"Original value:    {number:N}"
printfn $"Decremented value: {Decimal.Subtract(number, 1):N}"

// The example displays the following output:
//       Original value:    1,079.80
//       Decremented value: 1,078.80

Module Example
   Public Sub Main()
      Dim number As Decimal = 1079.8d
      Console.WriteLine("Original value:    {0:N}", number)
      Console.WriteLine("Decremented value: {0:N}", Decimal.Subtract(number, 1))
   End Sub
End Module
' The example displays the following output:
'       Original value:    1,079.80
'       Decremented value: 1,078.80

Van toepassing op

Zie ook