Kommentar
Åtkomst till den här sidan kräver auktorisering. Du kan prova att logga in eller ändra kataloger.
Åtkomst till den här sidan kräver auktorisering. Du kan prova att ändra kataloger.
Returns the lambda distribution parameter.
result_type lambda() const;
Remarks
The member function returns the stored value stored_lambda.
Example
// std_tr1__random__exponential_distribution_lambda.cpp
// compile with: /EHsc
#include <random>
#include <iostream>
typedef std::ranlux64_base_01 Myeng;
typedef std::exponential_distribution<double> Mydist;
int main()
{
Myeng eng;
Mydist dist(1.5);
Mydist::input_type engval = eng();
Mydist::result_type distval = dist(eng);
distval = distval; // to quiet "unused" warnings
engval = engval;
std::cout << "lambda == " << dist.lambda() << std::endl;
dist.reset(); // discard any cached values
std::cout << "a random value == " << dist(eng) << std::endl;
std::cout << "a random value == " << dist(eng) << std::endl;
std::cout << "a random value == " << dist(eng) << std::endl;
return (0);
}
lambda == 1.5 a random value == 0.223809 a random value == 0.168898 a random value == 0.176395
Requirements
Header: <random>
Namespace: std