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Tests if type has virtual destructor.
template<class Ty>
struct has_virtual_destructor;
Parameters
- Ty
The type to query.
Remarks
An instance of the type predicate holds true if the type Ty is a class that has a virtual destructor, otherwise it holds false.
Example
// std_tr1__type_traits__has_virtual_destructor.cpp
// compile with: /EHsc
#include <type_traits>
#include <iostream>
struct trivial
{
int val;
};
struct throws
{
throws() throw(int)
{
}
throws(const throws&) throw(int)
{
}
throws& operator=(const throws&) throw(int)
{
}
virtual ~throws()
{
}
int val;
};
int main()
{
std::cout << "has_virtual_destructor<trivial> == " << std::boolalpha
<< std::has_virtual_destructor<trivial>::value << std::endl;
std::cout << "has_virtual_destructor<throws> == " << std::boolalpha
<< std::has_virtual_destructor<throws>::value << std::endl;
return (0);
}
has_virtual_destructor<trivial> == false has_virtual_destructor<throws> == true
Requirements
Header: <type_traits>
Namespace: std