DateTimeFormatInfo.LongDatePattern Propriedade

Definição

Namespace:
System.Globalization
Assemblies:
mscorlib.dll, System.Globalization.dll
Assembly:
mscorlib.dll
Assembly:
System.Globalization.dll
Assembly:
netstandard.dll

Obtém ou define a cadeia de caracteres de formato personalizado para um valor de data longa.

public:
 property System::String ^ LongDatePattern { System::String ^ get(); void set(System::String ^ value); };
public string LongDatePattern { get; set; }
member this.LongDatePattern : string with get, set
Public Property LongDatePattern As String

Valor da propriedade

String

A cadeia de caracteres de formato personalizado para um valor de data longa.

Exceções

ArgumentNullException

A propriedade está sendo definida como null.

InvalidOperationException

A propriedade está sendo definida e o DateTimeFormatInfo objeto é somente leitura.

Exemplos

O exemplo a seguir exibe o valor da LongDatePattern propriedade para algumas culturas.

using System;
using System.Globalization;

public class SamplesDTFI  {

   public static void Main()  {

      // Displays the values of the pattern properties.
      Console.WriteLine( " CULTURE    PROPERTY VALUE" );
      PrintPattern( "en-US" );
      PrintPattern( "ja-JP" );
      PrintPattern( "fr-FR" );
   }

   public static void PrintPattern( String myCulture )  {

      DateTimeFormatInfo myDTFI = new CultureInfo( myCulture, false ).DateTimeFormat;
      Console.WriteLine( "  {0}     {1}", myCulture, myDTFI.LongDatePattern );
   }
}

/*
This code produces the following output. Note that the exact output format depends on the OS, the OS version, and the native globalization library used by the OS.

 CULTURE    PROPERTY VALUE
  en-US     dddd, MMMM d, yyyy
  ja-JP     yyyy年M月d日dddd
  fr-FR     dddd d MMMM yyyy

*/

Imports System.Globalization

Public Class SamplesDTFI

   Public Shared Sub Main()

      ' Displays the values of the pattern properties.
      Console.WriteLine(" CULTURE    PROPERTY VALUE")
      PrintPattern("en-US")
      PrintPattern("ja-JP")
      PrintPattern("fr-FR")

   End Sub

   Public Shared Sub PrintPattern(myCulture As [String])

      Dim myDTFI As DateTimeFormatInfo = New CultureInfo(myCulture, False).DateTimeFormat
      Console.WriteLine("  {0}     {1}", myCulture, myDTFI.LongDatePattern)

   End Sub

End Class

'This code produces the following output:
'
' CULTURE    PROPERTY VALUE
'  en-US     dddd, MMMM d, yyyy
'  ja-JP     yyyy'年'M'月'd'日'
'  fr-FR     dddd d MMMM yyyy
'

Comentários

A LongDatePattern propriedade define o formato específico da cultura de cadeias de caracteres de data que são retornadas por chamadas para os DateTime.ToString métodos e DateTimeOffset.ToString por cadeias de caracteres de formato composto que são fornecidas a cadeia de caracteres de formato padrão "D". O exemplo a seguir ilustra as relações entre as seguintes: a cadeia de caracteres de formato padrão "D", a cadeia de caracteres de formato personalizado retornada pela LongDatePattern propriedade e a representação específica da cultura de uma data.

using System;
using System.Globalization;

public class Example1
{
   public static void Main()
   {
      DateTime date1 = new DateTime(2011, 11, 12);
      string[] cultureNames = { "en-US", "fr-FR", "ru-RU", "de-DE" };
      Console.WriteLine("{0,-7} {1,-20} {2:D}\n", "Culture", "Long Date Pattern", "Date");
      foreach (var cultureName in cultureNames) {
         CultureInfo culture = CultureInfo.CreateSpecificCulture(cultureName);
         Console.WriteLine("{0,-7} {1,-20} {2}",
                           culture.Name,
                           culture.DateTimeFormat.LongDatePattern,
                           date1.ToString("D", culture));
      }
   }
}
// The example displays the following output:
//    Culture Long Date Pattern    Date
//
//    en-US   dddd, MMMM d, yyyy   Saturday, November 12, 2011
//    fr-FR   dddd d MMMM yyyy     samedi 12 novembre 2011
//    ru-RU   d MMMM yyyy 'г.'     12 ноября 2011 г.
//    de-DE   dddd, d. MMMM yyyy   Samstag, 12. November 2011

Imports System.Globalization

Module Example
   Public Sub Main()
      Dim date1 As Date = #11/12/2011#
      Dim cultureNames() As String = { "en-US", "fr-FR", "ru-RU", "de-DE" }
      Console.WriteLine("{0,-7} {1,-20} {2:D}", "Culture", "Long Date Pattern", "Date")
      Console.WriteLine()
      For Each cultureName In cultureNames
         Dim culture As CultureInfo = CultureInfo.CreateSpecificCulture(cultureName)
         Console.WriteLine("{0,-7} {1,-20} {2}", culture.Name, culture.DateTimeFormat.LongDatePattern, 
                           date1.ToString("D", culture))                 
      Next
   End Sub
End Module
' The example displays the following output:
'    Culture Long Date Pattern    Date
'
'    en-US   dddd, MMMM d, yyyy   Saturday, November 12, 2011
'    fr-FR   dddd d MMMM yyyy     samedi 12 novembre 2011
'    ru-RU   d MMMM yyyy 'г.'     12 ноября 2011 г.
'    de-DE   dddd, d. MMMM yyyy   Samstag, 12. November 2011

Consulte cadeias de caracteres de formato de data e hora personalizadas para especificadores de formato personalizado individuais que podem ser combinados para construir cadeias de caracteres de formato personalizado, como "dddd, dd MMMM yyyyy".

Você deve definir o separador de data no padrão de data longa como uma cadeia de caracteres exata em vez de usar o espaço reservado do separador de data. Por exemplo, para obter o padrão MM-DD-yyyyyy, defina o padrão de data longa como "MM-DD-yyyyyy".

O valor dessa propriedade poderá ser alterado se o calendário usado por uma cultura for alterado. Por exemplo, o exemplo a seguir mostra como a LongDatePattern propriedade de um CultureInfo objeto que representa a cultura árabe (Síria) muda quando o Calendar objeto usado pela cultura muda.

using System;
using System.Globalization;
using System.IO;

public class Example2
{
   public static void Main()
   {
      DateTime date1 = new DateTime(2011, 8, 7);
      CultureInfo ci = CultureInfo.CreateSpecificCulture("ar-SY");
      StreamWriter sw = new StreamWriter(@".\arSYCalendars.txt");

      sw.WriteLine("{0,-32} {1,-21} {2}\n",
                   "Calendar", "Long Date Pattern", "Example Date");
      foreach (var cal in ci.OptionalCalendars) {
         ci.DateTimeFormat.Calendar = cal;
         sw.WriteLine("{0,-32} {1,-21} {2}", GetCalendarName(cal),
                                             ci.DateTimeFormat.LongDatePattern,
                                             date1.ToString("D", ci));
      }
      sw.Close();
   }

   private static string GetCalendarName(Calendar cal)
   {
      string calName;
      calName = cal.GetType().Name.Substring(0, cal.GetType().Name.IndexOf("Cal"));
      if (calName.Equals("Gregorian")) {
         GregorianCalendar grCal = cal as GregorianCalendar;
         calName += String.Format("-{0}", grCal.CalendarType);
      }
      return calName;
   }
}
// The example generates the following output:
//    Calendar                         Long Date Pattern     Example Date
//
//    Gregorian-Localized              dd MMMM, yyyy         07 آب, 2011
//    UmAlQura                         dd/MMMM/yyyy          07/رمضان/1432
//    Hijri                            dd MMMM, yyyy         08 رمضان, 1432
//    Gregorian-USEnglish              dddd, MMMM dd, yyyy   Sunday, August 07, 2011
//    Gregorian-MiddleEastFrench       dddd, MMMM dd, yyyy   dimanche, août 07, 2011
//    Gregorian-TransliteratedEnglish  dddd, MMMM dd, yyyy   الأحد, أغسطس 07, 2011
//    Gregorian-TransliteratedFrench   dddd, MMMM dd, yyyy   الأحد, أوت 07, 2011

Imports System.Globalization
Imports System.IO

Module Example
   Public Sub Main()
      Dim date1 As Date = #8/7/2011#
      Dim ci As CultureInfo = CultureInfo.CreateSpecificCulture("ar-SY")
      Dim sw As New StreamWriter(".\arSYCalendars.txt") 

      sw.WriteLine("{0,-32} {1,-21} {2}", 
                   "Calendar", "Long Date Pattern", "Example Date")
      sw.WriteLine()
      For Each cal As Calendar In ci.OptionalCalendars
         ci.DateTimeFormat.Calendar = cal
         sw.WriteLine("{0,-32} {1,-21} {2}", GetCalendarName(cal), 
                                             ci.DateTimeFormat.LongDatePattern,
                                             date1.ToString("D", ci))
      Next     
      sw.Close()
   End Sub
   
   Private Function GetCalendarName(cal As Calendar) As String
      Dim calName As String
      calName = cal.GetType().Name.Substring(0, cal.GetType().Name.IndexOf("Cal"))
      If calName.Equals("Gregorian") Then
         Dim grCal As GregorianCalendar = DirectCast(cal, GregorianCalendar)
         calName += String.Format("-{0}", grCal.CalendarType)    
      End If
      Return calName
   End Function
End Module
' The example generates the following output:
'    Calendar                         Long Date Pattern     Example Date
'    
'    Gregorian-Localized              dd MMMM, yyyy         07 آب, 2011
'    UmAlQura                         dd/MMMM/yyyy          07/رمضان/1432
'    Hijri                            dd MMMM, yyyy         08 رمضان, 1432
'    Gregorian-USEnglish              dddd, MMMM dd, yyyy   Sunday, August 07, 2011
'    Gregorian-MiddleEastFrench       dddd, MMMM dd, yyyy   dimanche, août 07, 2011
'    Gregorian-TransliteratedEnglish  dddd, MMMM dd, yyyy   الأحد, أغسطس 07, 2011
'    Gregorian-TransliteratedFrench   dddd, MMMM dd, yyyy   الأحد, أوت 07, 2011

Aplica-se a

Confira também