Expression.Decrement Methode

public:
 static System::Linq::Expressions::UnaryExpression ^ Decrement(System::Linq::Expressions::Expression ^ expression);

public static System.Linq.Expressions.UnaryExpression Decrement(System.Linq.Expressions.Expression expression);

static member Decrement : System.Linq.Expressions.Expression -> System.Linq.Expressions.UnaryExpression

Public Shared Function Decrement (expression As Expression) As UnaryExpression

Parameters

Retouren

Een UnaryExpression die de afgebroken expressie vertegenwoordigt.

Voorbeelden

In het volgende codevoorbeeld ziet u hoe u een expressie maakt waarmee 1 van een bepaalde waarde wordt afgetrokken.

// Add the following directive to your file:
// using System.Linq.Expressions;

double num = 5.5;

// This expression represents a decrement operation
// that subtracts 1 from a value.
Expression decrementExpr = Expression.Decrement(
                            Expression.Constant(num)
                        );

// Print expression.
Console.WriteLine(decrementExpr.ToString());

// The following statement first creates an expression tree,
// then compiles it, and then executes it.
Console.WriteLine(
    Expression.Lambda<Func<double>>(decrementExpr).Compile()());

// The value of the variable did not change,
// because the expression is functional.
Console.WriteLine("object: " + num);

// This code example produces the following output:
//
// Decrement(5.5)
// 4.5
// object: 5.5

' Add the following directive to your file:
' Imports System.Linq.Expressions   

Dim num As Double = 5.5

' This expression represents a decrement operation 
' that subtracts 1 from a value. 
Dim decrementExpr As Expression = Expression.Decrement(
                            Expression.Constant(num)
                        )

' Print the expression.
Console.WriteLine(decrementExpr.ToString())

' The following statement first creates an expression tree,
' then compiles it, and then executes it.
Console.WriteLine(
    Expression.Lambda(Of Func(Of Double))(decrementExpr).Compile()())

' The value of the variable did not change,
' because the expression is functional.
Console.WriteLine("object: " & num)

' This code example produces the following output:
'
' Decrement(5.5)
' 4.5
' object: 5.5

Opmerkingen

Deze expressie is functioneel en wijzigt niet de waarde van het object dat eraan wordt doorgegeven.

public:
 static System::Linq::Expressions::UnaryExpression ^ Decrement(System::Linq::Expressions::Expression ^ expression, System::Reflection::MethodInfo ^ method);

public static System.Linq.Expressions.UnaryExpression Decrement(System.Linq.Expressions.Expression expression, System.Reflection.MethodInfo method);

static member Decrement : System.Linq.Expressions.Expression * System.Reflection.MethodInfo -> System.Linq.Expressions.UnaryExpression

Public Shared Function Decrement (expression As Expression, method As MethodInfo) As UnaryExpression

Parameters

Retouren

Een UnaryExpression die de afgebroken expressie vertegenwoordigt.

Opmerkingen

Deze expressie is functioneel en wijzigt niet de waarde van het object dat eraan wordt doorgegeven.