Refactorizar con un método de extensión

Este ejemplo se basa en el ejemplo anterior, Recuperar el texto de los párrafos, mediante la refactorización de la concatenación de cadenas con una función pura que se implementa como método de extensión.

El ejemplo anterior usaba el operador de consultas estándar Aggregate para concatenar varias cadenas en una sola.Sin embargo, resulta más eficaz escribir un método de extensión a tal efecto, ya que la consulta resultante es más pequeña y más simple.

Ejemplo

Este ejemplo procesa un documento WordprocessingML, recuperando los párrafos, así como el estilo y el texto de cada párrafo.Este ejemplo se basa en los ejemplos anteriormente vistos en este tutorial.

El ejemplo contiene varias sobrecargas del método StringConcatenate.

Puede obtener instrucciones acerca de cómo crear el documento de origen para este ejemplo en Crear el documento XML abierto de Office de origen.

Este ejemplo utiliza las clases que se encuentran en el ensamblado WindowsBase.Utiliza los tipos del espacio de nombres System.IO.Packaging.

public static class LocalExtensions
{
    public static string StringConcatenate(this IEnumerable<string> source)
    {
        StringBuilder sb = new StringBuilder();
        foreach (string s in source)
            sb.Append(s);
        return sb.ToString();
    }

    public static string StringConcatenate<T>(this IEnumerable<T> source,
        Func<T, string> func)
    {
        StringBuilder sb = new StringBuilder();
        foreach (T item in source)
            sb.Append(func(item));
        return sb.ToString();
    }

    public static string StringConcatenate(this IEnumerable<string> source, string separator)
    {
        StringBuilder sb = new StringBuilder();
        foreach (string s in source)
            sb.Append(s).Append(separator);
        return sb.ToString();
    }

    public static string StringConcatenate<T>(this IEnumerable<T> source,
        Func<T, string> func, string separator)
    {
        StringBuilder sb = new StringBuilder();
        foreach (T item in source)
            sb.Append(func(item)).Append(separator);
        return sb.ToString();
    }
}

<System.Runtime.CompilerServices.Extension()> _
Public Function StringConcatenate(ByVal source As IEnumerable(Of String)) As String
    Dim sb As StringBuilder = New StringBuilder()
    For Each s As String In source
        sb.Append(s)
    Next
    Return sb.ToString()
End Function

<System.Runtime.CompilerServices.Extension()> _
Public Function StringConcatenate(Of T)(ByVal source As IEnumerable(Of T), _
ByVal func As Func(Of T, String)) As String
    Dim sb As StringBuilder = New StringBuilder()
    For Each item As T In source
        sb.Append(func(item))
    Next
    Return sb.ToString()
End Function

<System.Runtime.CompilerServices.Extension()> _
Public Function StringConcatenate(Of T)(ByVal source As IEnumerable(Of T), _
ByVal separator As String) As String
    Dim sb As StringBuilder = New StringBuilder()
    For Each s As T In source
        sb.Append(s).Append(separator)
    Next
    Return sb.ToString()
End Function

<System.Runtime.CompilerServices.Extension()> _
Public Function StringConcatenate(Of T)(ByVal source As IEnumerable(Of T), _
ByVal func As Func(Of T, String), ByVal separator As String) As String
    Dim sb As StringBuilder = New StringBuilder()
    For Each item As T In source
        sb.Append(func(item)).Append(separator)
    Next
    Return sb.ToString()
End Function

Ejemplo

Hay cuatro sobrecargas del método StringConcatenate.Una sobrecarga simplemente toma una colección de cadenas y devuelve una sola cadena.Otra sobrecarga puede tomar una colección de cualquier tipo y un delegado que se proyecta de un singleton de la colección a una cadena.Hay dos sobrecargas más que permiten especificar una cadena de separación.

El código siguiente usa las cuatro sobrecargas.

string[] numbers = { "one", "two", "three" };

Console.WriteLine("{0}", numbers.StringConcatenate());
Console.WriteLine("{0}", numbers.StringConcatenate(":"));

int[] intNumbers = { 1, 2, 3 };
Console.WriteLine("{0}", intNumbers.StringConcatenate(i => i.ToString()));
Console.WriteLine("{0}", intNumbers.StringConcatenate(i => i.ToString(), ":"));

Dim numbers As String() = {"one", "two", "three"}

Console.WriteLine("{0}", numbers.StringConcatenate())
Console.WriteLine("{0}", numbers.StringConcatenate(":"))

Dim intNumbers As Integer() = {1, 2, 3}
Console.WriteLine("{0}", intNumbers.StringConcatenate(Function(i) i.ToString()))
Console.WriteLine("{0}", intNumbers.StringConcatenate(Function(i) i.ToString(), ":"))

Este ejemplo genera el siguiente resultado:

onetwothree
one:two:three:
123
1:2:3:

Ejemplo

Ahora, el ejemplo puede modificarse para aprovechar el nuevo método de extensión:

public static class LocalExtensions
{
    public static string StringConcatenate(this IEnumerable<string> source)
    {
        StringBuilder sb = new StringBuilder();
        foreach (string s in source)
            sb.Append(s);
        return sb.ToString();
    }

    public static string StringConcatenate<T>(this IEnumerable<T> source,
        Func<T, string> func)
    {
        StringBuilder sb = new StringBuilder();
        foreach (T item in source)
            sb.Append(func(item));
        return sb.ToString();
    }

    public static string StringConcatenate(this IEnumerable<string> source, string separator)
    {
        StringBuilder sb = new StringBuilder();
        foreach (string s in source)
            sb.Append(s).Append(separator);
        return sb.ToString();
    }

    public static string StringConcatenate<T>(this IEnumerable<T> source,
        Func<T, string> func, string separator)
    {
        StringBuilder sb = new StringBuilder();
        foreach (T item in source)
            sb.Append(func(item)).Append(separator);
        return sb.ToString();
    }
}

class Program
{
    static void Main(string[] args)
    {
        const string fileName = "SampleDoc.docx";

        const string documentRelationshipType =
          "https://schemas.openxmlformats.org/officeDocument/2006/relationships/officeDocument";
        const string stylesRelationshipType =
          "https://schemas.openxmlformats.org/officeDocument/2006/relationships/styles";
        const string wordmlNamespace =
          "https://schemas.openxmlformats.org/wordprocessingml/2006/main";
        XNamespace w = wordmlNamespace;

        XDocument xDoc = null;
        XDocument styleDoc = null;

        using (Package wdPackage = Package.Open(fileName, FileMode.Open, FileAccess.Read))
        {
            PackageRelationship docPackageRelationship =
              wdPackage.GetRelationshipsByType(documentRelationshipType).FirstOrDefault();
            if (docPackageRelationship != null)
            {
                Uri documentUri = PackUriHelper.ResolvePartUri(new Uri("/", UriKind.Relative),
                  docPackageRelationship.TargetUri);
                PackagePart documentPart = wdPackage.GetPart(documentUri);

                //  Load the document XML in the part into an XDocument instance.
                xDoc = XDocument.Load(XmlReader.Create(documentPart.GetStream()));

                //  Find the styles part. There will only be one.
                PackageRelationship styleRelation =
                  documentPart.GetRelationshipsByType(stylesRelationshipType).FirstOrDefault();
                if (styleRelation != null)
                {
                    Uri styleUri =
                      PackUriHelper.ResolvePartUri(documentUri, styleRelation.TargetUri);
                    PackagePart stylePart = wdPackage.GetPart(styleUri);

                    //  Load the style XML in the part into an XDocument instance.
                    styleDoc = XDocument.Load(XmlReader.Create(stylePart.GetStream()));
                }
            }
        }

        string defaultStyle =
            (string)(
                from style in styleDoc.Root.Elements(w + "style")
                where (string)style.Attribute(w + "type") == "paragraph" &&
                      (string)style.Attribute(w + "default") == "1"
                select style
            ).First().Attribute(w + "styleId");

        // Find all paragraphs in the document.
        var paragraphs =
            from para in xDoc
                         .Root
                         .Element(w + "body")
                         .Descendants(w + "p")
            let styleNode = para
                            .Elements(w + "pPr")
                            .Elements(w + "pStyle")
                            .FirstOrDefault()
            select new
            {
                ParagraphNode = para,
                StyleName = styleNode != null ?
                    (string)styleNode.Attribute(w + "val") :
                    defaultStyle
            };

        // Retrieve the text of each paragraph.
        var paraWithText =
            from para in paragraphs
            select new
            {
                ParagraphNode = para.ParagraphNode,
                StyleName = para.StyleName,
                Text = para
                       .ParagraphNode
                       .Elements(w + "r")
                       .Elements(w + "t")
                       .StringConcatenate(e => (string)e)
            };

        foreach (var p in paraWithText)
            Console.WriteLine("StyleName:{0} >{1}<", p.StyleName, p.Text);
    }
}

Imports <xmlns:w="https://schemas.openxmlformats.org/wordprocessingml/2006/main">

Module Module1
    <System.Runtime.CompilerServices.Extension()> _
    Public Function StringConcatenate(ByVal source As IEnumerable(Of String)) As String
        Dim sb As StringBuilder = New StringBuilder()
        For Each s As String In source
            sb.Append(s)
        Next
        Return sb.ToString()
    End Function

    <System.Runtime.CompilerServices.Extension()> _
    Public Function StringConcatenate(Of T)(ByVal source As IEnumerable(Of T), _
    ByVal func As Func(Of T, String)) As String
        Dim sb As StringBuilder = New StringBuilder()
        For Each item As T In source
            sb.Append(func(item))
        Next
        Return sb.ToString()
    End Function

    <System.Runtime.CompilerServices.Extension()> _
    Public Function StringConcatenate(Of T)(ByVal source As IEnumerable(Of T), _
    ByVal separator As String) As String
        Dim sb As StringBuilder = New StringBuilder()
        For Each s As T In source
            sb.Append(s).Append(separator)
        Next
        Return sb.ToString()
    End Function

    <System.Runtime.CompilerServices.Extension()> _
    Public Function StringConcatenate(Of T)(ByVal source As IEnumerable(Of T), _
    ByVal func As Func(Of T, String), ByVal separator As String) As String
        Dim sb As StringBuilder = New StringBuilder()
        For Each item As T In source
            sb.Append(func(item)).Append(separator)
        Next
        Return sb.ToString()
    End Function

    ' Following function is required because VB does not support short circuit evaluation
    Private Function GetStyleOfParagraph(ByVal styleNode As XElement, _
                                         ByVal defaultStyle As String) As String
        If (styleNode Is Nothing) Then
            Return defaultStyle
        Else
            Return styleNode.@w:val
        End If
    End Function

    Sub Main()
        Dim fileName = "SampleDoc.docx"

        Dim documentRelationshipType = _
          "https://schemas.openxmlformats.org/officeDocument/2006/relationships/officeDocument"
        Dim stylesRelationshipType = _
          "https://schemas.openxmlformats.org/officeDocument/2006/relationships/styles"
        Dim wordmlNamespace = _
          "https://schemas.openxmlformats.org/wordprocessingml/2006/main"

        Dim xDoc As XDocument = Nothing
        Dim styleDoc As XDocument = Nothing
        Using wdPackage As Package = Package.Open(fileName, FileMode.Open, FileAccess.Read)
            Dim docPackageRelationship As PackageRelationship = _
              wdPackage.GetRelationshipsByType(documentRelationshipType).FirstOrDefault()
            If (docPackageRelationship IsNot Nothing) Then
                Dim documentUri As Uri = PackUriHelper.ResolvePartUri(New Uri("/", UriKind.Relative), _
                  docPackageRelationship.TargetUri)
                Dim documentPart As PackagePart = wdPackage.GetPart(documentUri)

                '  Load the document XML in the part into an XDocument instance.
                xDoc = XDocument.Load(XmlReader.Create(documentPart.GetStream()))

                '  Find the styles part. There will only be one.
                Dim styleRelation As PackageRelationship = _
                  documentPart.GetRelationshipsByType(stylesRelationshipType).FirstOrDefault()
                If (styleRelation IsNot Nothing) Then
                    Dim styleUri As Uri = _
                      PackUriHelper.ResolvePartUri(documentUri, styleRelation.TargetUri)
                    Dim stylePart As PackagePart = wdPackage.GetPart(styleUri)

                    '  Load the style XML in the part into an XDocument instance.
                    styleDoc = XDocument.Load(XmlReader.Create(stylePart.GetStream()))
                End If
            End If
        End Using

        Dim defaultStyle As String = _
            ( _
                From style In styleDoc.Root.<w:style> _
                Where style.@w:type = "paragraph" And _
                      style.@w:default = "1" _
                Select style _
            ).First().@w:styleId

        ' Find all paragraphs in the document.
        Dim paragraphs = _
            From para In xDoc.Root.<w:body>...<w:p> _
        Let styleNode As XElement = para.<w:pPr>.<w:pStyle>.FirstOrDefault _
        Select New With { _
            .ParagraphNode = para, _
            .StyleName = GetStyleOfParagraph(styleNode, defaultStyle) _
        }

        ' Retrieve the text of each paragraph.
        Dim paraWithText = _
            From para In paragraphs _
            Select New With { _
                .ParagraphNode = para.ParagraphNode, _
                .StyleName = para.StyleName, _
                .Text = para.ParagraphNode.<w:r>.<w:t>.StringConcatenate(Function(e) CStr(e)) _
            }

        For Each p In paraWithText
            Console.WriteLine("StyleName:{0} >{1}<", p.StyleName, p.Text)
        Next

    End Sub
End Module

Este ejemplo genera el siguiente resultado cuando se aplica al documento descrito en Crear el documento XML abierto de Office de origen.

StyleName:Heading1 >Parsing WordprocessingML with LINQ to XML<
StyleName:Normal ><
StyleName:Normal >The following example prints to the console.<
StyleName:Normal ><
StyleName:Code >using System;<
StyleName:Code ><
StyleName:Code >class Program {<
StyleName:Code >    public static void (string[] args) {<
StyleName:Code >        Console.WriteLine("Hello World");<
StyleName:Code >    }<
StyleName:Code >}<
StyleName:Normal ><
StyleName:Normal >This example produces the following output:<
StyleName:Normal ><
StyleName:Code >Hello World<

Tenga en cuenta que esta refactorización es una variante de refactorizar en una función pura.El siguiente tema presentará la idea de factorizar en funciones puras con mayor detalle.

Pasos siguientes

El siguiente ejemplo muestra cómo refactorizar este código de otra forma, mediante las funciones puras:

Refactorizar utilizando una función pura

Vea también

Conceptos

Tutorial: manipular contenido en un documento WordprocessingML

Refactorizar en funciones puras

Last updated on 2012-08-31

Refactorizar con un método de extensión

Ejemplo

Ejemplo

Ejemplo

Pasos siguientes

Vea también

Conceptos

Recursos adicionales